How many moles of KCl are present in 95.3 mL of 2.10M KCl

asked May 19, 2024 66.3k views

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4 votes

Answer:

0.2

Step-by-step explanation:

Mol of KCl

2.10 x (95.3÷1000)

=0.20013mol

Hugo Ferreira answered May 25, 2024

8.3k points

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