Answer:
Vertex is at (1,1)
Explanation:
The y value of the vertex is given by the expression -b/2a, where a and b are the coefficients in a quadratic equation:
y = ax^2 + bx + c
For the quadratic y = 3x^2 - 6x + 4,
a is 3 and b is -6
The y value of the vertex is -b/2a
-b/2a
- (-6)/(2*(3)) = 1
The y value at the vertex is 1. Use y=1 to find the value of x:
y = 3x^2 - 6x + 4
1 = 3x^2 - 6x + 4
3x^2 - 6x + 3 = 0
x = 1
The vertex is (1,1)
See the attached graph.