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CAN SOMEONE PLEASE HELP ME PLEASE THIS IS DUE IN A FEW MINUTES

CAN SOMEONE PLEASE HELP ME PLEASE THIS IS DUE IN A FEW MINUTES-example-1
User Jlw
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1 Answer

1 vote

Answer:

Vertex is at (1,1)

Explanation:

The y value of the vertex is given by the expression -b/2a, where a and b are the coefficients in a quadratic equation:

y = ax^2 + bx + c

For the quadratic y = 3x^2 - 6x + 4,

a is 3 and b is -6

The y value of the vertex is -b/2a

-b/2a

- (-6)/(2*(3)) = 1

The y value at the vertex is 1. Use y=1 to find the value of x:

y = 3x^2 - 6x + 4

1 = 3x^2 - 6x + 4

3x^2 - 6x + 3 = 0

x = 1

The vertex is (1,1)

See the attached graph.

CAN SOMEONE PLEASE HELP ME PLEASE THIS IS DUE IN A FEW MINUTES-example-1
User Bravo Yeung
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