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Solve absolute value inequalities |x+5|>-1 and b) |3-x|<5

User Greg Ennis
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Answer:

|x+5| > -1 is true for all x-values.

|3-x| < 5 is true when -2 < x < 8.

Explanation:

Given the inequality:


\displaystyle

The inequality is true for all values of x. This is because no matter what real numbers/values you substitute in x-term, the output will always be positive, which is greater than negative.

Given another inequality for part b:


\displaystyle

This inequality can have a specific interval as the right side is greater than the negative. Therefore, apply the definition of absolute value:

For x ≥ 0,


\displaystyle{3-x < 5}\\\\\displaystyle{3-5 < x}\\\\\displaystyle{-2 < x}\\\\\displaystyle{x > -2}

For x < 0,


\displaystyle{-(3-x) < 5}\\\\\displaystyle{-3+x < 5}\\\\\displaystyle{x < 8}

Therefore, when combining both intervals, we have the following:


\displaystyle{-2 < x < 8}

Hence, the inequality is true for -2 < x < 8.

User Max Wen
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