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13 What are the roots of x in -10x² + 12x - 9 =0?. 6i√6 -12 606 ± 336 ±i√24 200 2i√6 31/24 20
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13

What are the roots of x in -10x² + 12x - 9 =0?.

6i√6
-12 606
±

336

±i√24
200
2i√6
31/24
20

13 What are the roots of x in -10x² + 12x - 9 =0?. 6i√6 -12 606 ± 336 ±i√24 200 2i-example-1
User Shweta Chandel
by
8.7k points

1 Answer

5 votes

Answer:

B

Explanation:


-10x^2+12x-9=0 \\ \\ x=(-12 \pm √(12^2-4(-10)(-9)))/(2(-10)) \\ \\ x=(-12 \pm √(-216))/(-20) \\ \\ x=(3)/(5) \pm (i√(54))/(10) \\ \\ x=(3)/(5) \pm (3i\sqrt 6)/(10)

User Mamidon
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