Question

A particle having a mass of 100g moves with a final velocity with an acceleration of 15 m/s^2 in a 4 seconds with an initial velocity of 3m/s^2. Find

a.)final velocity
b.)the force

Answer 1

Vf = 63 m/s

F = 1.5 N

Step-by-step explanation:

Given data:

Mass = m = 100 g = 0.1 kg

Time = t = 4 s

Acceleration = a = 15 m/s²

Initial velocity = Vi = 3 m/s

Required:

1. Final velocity = Vf = ?
2. Force = F = ?

Formula:

1. Vf = Vi + at (First equation of motion)
2. F = ma (Newton's second law of motion)

Solution:

`\rule[225]{225}{2}`

Final velocity:

Put the given data in the formula.

Vf = 3 + (15)(4)

Vf = 3 + 60

Vf = 63 m/s

`\rule[225]{225}{2}`

Force:

Put the given data in the formula.

F = ma

F = (0.1)(15)

F = 1.5 N

`\rule[225]{225}{2}`