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What is the area of the object above?

What is the area of the object above?-example-1
User Dan Me
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2 Answers

1 vote

We can divide the figure into two parts, the upper part, and lower part, shown divided by the blue line. We can find the area of both of these and add them together, which will be our final answer.

We multiply the length and width of the upper figure and get 8in*6in= 48in^2.

For the lower figure, we get 20in*10in=200in^2.

We add the two together and get our final answer: (D) 248in^2

What is the area of the object above?-example-1
User Ianna
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8.6k points
4 votes

Answer:


\huge\boxed{\sf 248\ in.\²}

Explanation:

The given figure is made up of 2 rectangles.

Area of rectangle:

  • Area of rectangle = length × width

Area of rectangle 1:

Length = 12 in., width = 10 in.

= length × width

= 12 × 10

= 120 in.²

Area of rectangle 2:

Length = 16 in. , width = 8 in.

= length × width

= 16 × 8

= 128 in.²

Total Area:

= Area of rectangle 1 + rectangle 2

= 120 + 128

= 248 in.²


\rule[225]{225}{2}

User Pgmura
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8.1k points

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