Question

​Calculate the concentration of oxalate ion (C2O42–) in a 0.175 M solution of oxalic acid (C2H2O4). [For oxalic acid, Ka1 = 6.5  10–2, Ka2 = 6.1  10–5.]

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Answer 1

listed below

Step-by-step explanation:

Since [HC2O4–] is 0 M (fully converted to C2O42–), the equation simplifies to:

x = √(6.1 × 10–5) ≈ 7.8 × 10–3 M

So, the concentration of oxalate ion (C2O42–) in the 0.175 M solution of oxalic acid (C2H2O4) is approximately 7.8 × 10–3 M.