Question

Please solve this question fast!!!!​

Answer 1

Hi,

Explanation:

`A=\begin{bmatrix}2 & -6 \\14 & -7 \end{bmatrix}\\\\B=\begin{bmatrix}3 & 1 \\16 & -8 \end{bmatrix}\\\\\\\left\{\begin{array}ccc2P-3Q&=&A&3&2\\3P-2Q&=&B&-2&-3\\\end{array} \right.\\\\\\\left\{\begin{array}{ccc}0P-5Q&=&3A-2B\\-5P+0Q&=&2A-3B\\\end{array} \right.`

`\left\{\begin{array}{ccc}Q&=&(-1)/(5)*( 3A-2B)\\P&=&(-1)/(5)*(2A-3B)\\\end{array} \right.\\\\\\\left\{\begin{array}{ccc}Q&=&(-1)/(5)*( 3*\begin{bmatrix}2 & -6 \\14 & -7 \end{bmatrix}-2*\begin{bmatrix}3 & 1 \\16 & -8 \end{bmatrix})\\\\P&=&(-1)/(5)*(2*\begin{bmatrix}2 & -6 \\14 & -7 \end{bmatrix}-3*\begin{bmatrix}3 & 1 \\16 & -8 \end{bmatrix})\\\end{array} \right.`

`\left\{\begin{array}{ccc}Q&=&(-1)/(5)*( \begin{bmatrix}6 & -18 \\42 & -21 \end{bmatrix}+\begin{bmatrix}-6 & -2 \\-32 &16 \end{bmatrix})\\\\P&=&(-1)/(5)*(\begin{bmatrix}4 & -12 \\28 & -14 \end{bmatrix}+\begin{bmatrix}-9 & -3 \\-48 & 24 \end{bmatrix})\\\end{array} \right.\\\\\\\left\{\begin{array}{ccc}Q&=&(-1)/(5)* \begin{bmatrix}0 & -20 \\10 & -5 \end{bmatrix}\\\\P&=&(-1)/(5)*\begin{bmatrix}-5 & -15 \\-20 & 10 \end{bmatrix}\\\\\end{array} \right.`

`\left\{\begin{array}{ccc}P&=&\begin{bmatrix}1 & 3 \\4 & -2 \end{bmatrix}\\\\Q&=&\begin{bmatrix}0 & 4 \\2 & 1 \end{bmatrix}\\\\\end{array} \right.`