Question

If cos(0) = 3 over 10 what is sin(0)

Answer 1

D)
`(√(91))/(10)`

Explanation:

`\cos\theta=\frac{\text{Adjacent}}{\text{Hypotenuse}}=(3)/(10)\\\\\sin\theta=\frac{\text{Opposite}}{\text{Hypotenuse}}=(√(10^2-3^2))/(10)=(√(100-9))/(10)=(√(91))/(10)`