2^2017+2^2015 divided by 2^2014-2^2015

asked Nov 12, 2024 143k views

1 vote

by Ikida

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$\displaystyle(2^(2017)+2^(2015))/(2^(2014)-2^(2015))= (2^(2015)(2^2+1))/(2^(2014)(1-2)) =(2*5)/(-1) =-10$

Bjarke answered Nov 18, 2024

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