Answer: f(x) = (-2/3)(x + 2)(x - 1)(x - 3)
Explanation:
To find the polynomial of least degree with the given zeros and y-intercept, we use the factored form of a polynomial. For a polynomial of degree 3, the factored form is:
f(x) = a(x - r1)(x - r2)(x - r3)
where a is the leading coefficient and r1, r2, and r3 are the zeros of the polynomial.
Given zeros at x = -2, x = 1, and x = 3, we can write the factored form as:
f(x) = a(x + 2)(x - 1)(x - 3)
Now, we need to find the value of the leading coefficient, a. To do that, we use the y-intercept, which is given as (0, -4). Since the y-intercept is a point on the graph of the polynomial, we can substitute x = 0 and y = -4 into the factored form:
-4 = a(0 + 2)(0 - 1)(0 - 3)
Simplify:
-4 = a(2)(-1)(-3)
-4 = 6a
Now, solve for a:
a = -4/6
a = -2/3
Finally, we have the factored form of the polynomial:
f(x) = (-2/3)(x + 2)(x - 1)(x - 3)