Question

P=(-7,-6) Q=(6,10) R=(-3,-9) S=(-3,7) Find PQ+RS

Answer 1

Vector PQ = [6 - (-7)] i + [10 - (-6)] j = 13 i + 16 j

Vector RS = [3 - (-3)] i + [7 - (-9)] j = 16 j

PQ + RS = 13 i + 32 j adding vectors

magnitude PQ + RS = [13^2 + 32^2]^1/2 = 34.5

tan θ = 32 / 13 = 67.9 deg