65.3k views
1 vote
Find an equation for the line that passes through the points −5, 1 and −1, 2.

2 Answers

0 votes

Answer:

y= 0.25x + 2.25

Explanation:

To find the equation of the line we must use y=mx+c where m is the gradient and c is the y intercept.

We need to find the gradient and y-intercept to construct an equation. To find the gradient we can use the formula m=
(y2-y1)/(x2-x1) I will take y1 as 1 and y2 as 2. You can use the opposite also y1 as 2 and y2 as 1.

m= (2-1)/(-1-(-5))= 0.25

We have the gradient but we don't have the y-intercept. We can find it by taking any one of the coordinates and plugging all the values we have into y=mx+c. I will take the 1st coordinate.

y= 0.25x + c

1= 0.25(-5) + c

1= -1.25 + c

c= 1+1.25= 2.25

Now plug in the values of the gradient and y-intercept into y=mx+c.

y= 0.25x + 2.25

User Adrian Smith
by
8.9k points
1 vote

Answer:

4 y = x + 9.

Explanation:

Let the point A be (-5, 1) and point B be (-1, 2).

The slope of the straight line passing through A and B is given by:

m = (y2 - y1) / (x2 - x1)

= (2-1)/(-1-(-5)) = 1/4.

Equation of the straight line that passes through A(-5,1) and has a slope of 1/4 is given by

y - 1 = 1/4 × (x +5)

=> y = 1+5/4 +x/4

=> 4 y = x + 9.

User Nyteshade
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories