Explanation:
a.
The length of the major axis = 2a = 100' => a =50'.
The length of the minor axis = 2b = 60' => b = 30'.
Let's say that the X-axis is along the length of the centre of the court room. And, the Y-axis is along the width in the centre. Let the centre point of the court room be called the origin denoted by O with the coordinates (0,0).
The equation of the ellipse:
x²/50² + y²/30² = 1.
b. e = eccentricity of the ellipse.
e² = 1 - b²/a² = 1 - 900/2500 = 16/25
e = 4/5 .
The focii F1 and F2 are at a distance a × e = 32' from the origin 0 on either side, on the major axis.
Vertices A (-a, 0) = (-50 ', 0), : B = (a,0) = (50' ,0) .
C ( -b,0) = (0, -30) ; D(b,0) = (0,30).
The defining feature of an ellipse is that for any point P (x, y) on the ellipse, the sum of the distances PF1 and PF2 to the focii is a constant.
c.
We would stand at the Focii. They're at a distance= a×e = 32' away from the centre.
d. The Focii are 64 feet away from each other.
e. From the centre O, the nearest wall is at the distance= b = 30 '.