Question

A ball is dropped from a cliff that is 135 m high. The relationship between the height of the ball, h, in metres, and time, t, in seconds, can be represented by the equation h = −4. 9t2 + 135. Which is closest to the height of the ball after 2. 1 seconds?

Answer 1

Plugging in 2.1 seconds for t, we get h = -4.9 * 2.1^2 + 135 = -4.9 * 4.41 + 135 = 106.49 m.

The height of the ball after 2.1 seconds is closest to 106 m.