Answer:
To calculate the amount of heat required to vaporize a given amount of water, we use the formula:
Q = m * ΔHvap
Where:
Q = Heat required (in joules)
m = Mass of water (in grams)
ΔHvap = Enthalpy of vaporization of water (in joules per gram)
The enthalpy of vaporization of water is the amount of energy required to convert one gram of water from liquid to vapor at a given temperature. For water at 100°C and atmospheric pressure, the enthalpy of vaporization is approximately 2260 joules per gram.
Let's calculate the heat required to vaporize 40.3 grams of water at 100°C:
Q = 40.3 g * 2260 J/g
Q = 90938 joules
So, approximately 90,938 joules of heat are required to vaporize 40.3 grams of water at 100°C.
Step-by-step explanation:
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