Question

Jill's present weight is 14 pounds less than her weight a year ago. If her weight at that time was her present weight in pounds? 8 of her present weight, what is​

Answer 1

Explanation:

x = present weight

x + 14 = weight one year ago <====

9/8 x = weight one year ago <==== these are equal:

x+14 = 9/8 x <==== solve for x

1/8x = 14

x = 14 * 8

x = present weight = 112 lb

Answer 2

112 lb

Explanation:

Corrected Question:

Jill's present weight is 14 pounds less than her weight a year ago. If her weight at that time was 9/8 of her present weight what is her present weight in pounds?

Let x = present weight.

Let y = her weight a year ago.

"Jill's present weight is 14 pounds less than her weight a year ago."

x = y - 14

"her weight at that time was 9/8 of her present weight"

y = 9/8 x

We have a system of 2 equations:

x = y - 14

y = 9/8 x

Since the second equation is already solved for y, we can easily use the substitution method. Substitute "9/8 x" for y in the first equation.

x = 9/8 x - 14

Multiply both sides by 8 to get rid of the denominator.

8x = 8 × 9/8 x - 14 × 8

8x = 9x - 112

Subtract 9x from both sides.

-x = -112

Divide both sides by -1.

x = 112

Answer: 112 lb