Question

"

What is the sensitivity of a device with an input voltage range
of 5 mV to 100 mV and an output current of between 4 mA to 20
mA?
Determine the out value of the device above if the measured out
value is 12.36
"

Answer 1

The output value of the device for a measured input of 12.36 mV is approximately 6.0762 mA.

Step-by-step explanation:

To calculate the sensitivity of the device, we need to determine how much the output current changes for a given change in the input voltage. Sensitivity is usually represented as the change in output current per unit change in input voltage (mA/mV).

Sensitivity (S) = (Change in output current) / (Change in input voltage)

Given:

Input voltage range (Vin_min to Vin_max) = 5 mV to 100 mV

Output current range (Iout_min to Iout_max) = 4 mA to 20 mA

Change in input voltage (ΔVin) = Vin_max - Vin_min = 100 mV - 5 mV = 95 mV

Change in output current (ΔIout) = Iout_max - Iout_min = 20 mA - 4 mA = 16 mA

Sensitivity (S) = ΔIout / ΔVin

Sensitivity (S) = 16 mA / 95 mV

Now, let's calculate the sensitivity:

Sensitivity (S) = 0.1684 mA/mV (approximately)

Now, to determine the output value for a measured input of 12.36 mV, we can use the sensitivity:

Change in output current (ΔIout) = Sensitivity (S) * Change in input voltage (ΔVin)

ΔIout = 0.1684 mA/mV * 12.36 mV

Now, calculate the output value (Iout):

Iout = Iout_min + ΔIout

Iout = 4 mA + (0.1684 mA/mV * 12.36 mV)

Iout ≈ 4 mA + 2.0762 mA ≈ 6.0762 mA

So, the output value of the device for a measured input of 12.36 mV is approximately 6.0762 mA.