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Let S and T be defined by

Which of the following are correct?

S is an open set.

S does not have any accumulation point.

i is an accumulation point of S.

T is an openset.

T is a closed set.

i is an accumulation point of T.

1 is an accumulation point of set T.

S is neither open nor closed set.

S is a closed set.

T is neither open nor closed set.

0 is an accumulation point of set S.

T does not have any accumulation point.

User Nikron
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1 Answer

4 votes

Let's analyze each statement:

1) S is an open set.

- False. S is not open because it does not contain all points in some neighborhood of each of its points. For example, 1 is in S but there is no open ball around 1 that is fully contained in S.

2) S does not have any accumulation point.

- False. 1 is an accumulation point of S.

3) i is an accumulation point of S.

- True. Every open ball centered at i contains points of S.

4) T is an open set.

- False. T is not open because it does not contain all points in a neighborhood of each of its points. For example, 1 is in T but no open ball around 1 is fully contained in T.

5) T is a closed set.

- True. T contains all its boundary points.

6) i is an accumulation point of T.

- True. Every open ball centered at i contains points of T.

7) 1 is an accumulation point of set T.

- True. Every open ball centered at 1 contains points of T.

8) S is neither open nor closed set.

- True. S is not open or closed.

9) S is a closed set.

- False. S is not closed because it does not contain its boundary point 1.

10) T is neither open nor closed set.

- False. T is a closed set.

11) 0 is an accumulation point of set S.

- False. No open ball centered at 0 contains any points of S.

12) T does not have any accumulation point.

- False. i and 1 are accumulation points of T.

User Lamas
by
8.4k points

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