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Calculate the [OH-] and the pH of a solution with [H+]= 1.8 x 10^-10 M at 25 °C.

User Haran
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Answer: The [OH-] of the solution is approximately 5.56 x 10^-5 M, and the pH of the solution is approximately 9.74 at 25 °C.

Step-by-step explanation:

To calculate the [OH-] and pH of a solution with [H+] = 1.8 x 10^-10 M at 25 °C, we can use the relationship between the concentration of hydrogen ions ([H+]) and hydroxide ions ([OH-]) in a water solution at a given temperature:

Kw = [H+] * [OH-]

where Kw is the ion product constant of water, which is equal to 1.0 x 10^-14 at 25 °C.

We are given [H+] = 1.8 x 10^-10 M, and we need to find [OH-] and pH.

Step 1: Calculate [OH-]

Kw = [H+] * [OH-]

1.0 x 10^-14 = (1.8 x 10^-10) * [OH-]

Now, solve for [OH-]:

[OH-] = 1.0 x 10^-14 / 1.8 x 10^-10

[OH-] ≈ 5.56 x 10^-5 M

Step 2: Calculate pH

pH is defined as the negative logarithm (base 10) of the hydrogen ion concentration ([H+]):

pH = -log[H+]

pH = -log(1.8 x 10^-10)

pH ≈ 9.74

Step 3: Check for consistency using Kw

Now, let's check if the calculated values are consistent with the ion product constant of water (Kw):

Kw = [H+] * [OH-]

1.0 x 10^-14 = (1.8 x 10^-10) * (5.56 x 10^-5)

The calculated value for Kw is approximately 1.0 x 10^-14, which is consistent with the ion product constant of water at 25 °C.

Conclusion:

The [OH-] of the solution is approximately 5.56 x 10^-5 M, and the pH of the solution is approximately 9.74 at 25 °C.

User Renny
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