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Find a polynomial function with the zeros -3,2 ,4 whose graph passes through the point (7,300).

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Answer:

f(x) = c(x + 3)(x - 2)(x - 4)

300 = c(10)(5)(3)

150c = 300, so c = 2

f(x) = 2(x + 3)(x - 2)(x - 4)

= 2(x + 3)(x² - 6x + 8)

= 2(x³ - 6x² + 8x + 3x² - 18x + 24)

= 2(x³ - 3x² - 10x + 24)

= 2x³ - 6x² - 20x + 48

User Jonathan Olson
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