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5 votes
3.0 mol Na reacts with 1.4 mol

F2 according to the equation below:
2Na+ F₂ → 2NaF
How many moles of NaF form
from 3.0 mol Na?
[?] mol NaF
Round your answer to the tenths place.

User TerryTsao
by
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1 Answer

5 votes

Let's first identify the stoichiometric ratio between Na and NaF from the balanced chemical equation:

2Na + F₂ → 2NaF

According to the equation, 2 moles of Na react with 1 mole of F₂ to produce 2 moles of NaF.

Now, we are given 3.0 moles of Na. To find the moles of NaF formed, we can set up a simple proportion:

(3.0 moles Na) : (x moles NaF) = (2 moles NaF) : (1 mole Na)

Cross-multiply:

3.0 moles Na * 2 moles NaF = x moles NaF * 1 mole Na

6.0 moles NaF = x moles NaF

Now, divide both sides by the coefficient of NaF:

x moles NaF = 6.0 moles NaF

Therefore, 3.0 moles of Na react to form 6.0 moles of NaF. Rounded to the tenths place, the answer is 6.0 mol NaF.

User Alin Razvan
by
8.3k points