Let's first identify the stoichiometric ratio between Na and NaF from the balanced chemical equation:
2Na + F₂ → 2NaF
According to the equation, 2 moles of Na react with 1 mole of F₂ to produce 2 moles of NaF.
Now, we are given 3.0 moles of Na. To find the moles of NaF formed, we can set up a simple proportion:
(3.0 moles Na) : (x moles NaF) = (2 moles NaF) : (1 mole Na)
Cross-multiply:
3.0 moles Na * 2 moles NaF = x moles NaF * 1 mole Na
6.0 moles NaF = x moles NaF
Now, divide both sides by the coefficient of NaF:
x moles NaF = 6.0 moles NaF
Therefore, 3.0 moles of Na react to form 6.0 moles of NaF. Rounded to the tenths place, the answer is 6.0 mol NaF.