Question

3.0 mol Na reacts with 1.4 mol

F2 according to the equation below:
2Na+ F₂ → 2NaF
How many moles of NaF form
from 3.0 mol Na?
[?] mol NaF
Round your answer to the tenths place.

Answer 1

Let's first identify the stoichiometric ratio between Na and NaF from the balanced chemical equation:

2Na + F₂ → 2NaF

According to the equation, 2 moles of Na react with 1 mole of F₂ to produce 2 moles of NaF.

Now, we are given 3.0 moles of Na. To find the moles of NaF formed, we can set up a simple proportion:

(3.0 moles Na) : (x moles NaF) = (2 moles NaF) : (1 mole Na)

Cross-multiply:

3.0 moles Na * 2 moles NaF = x moles NaF * 1 mole Na

6.0 moles NaF = x moles NaF

Now, divide both sides by the coefficient of NaF:

x moles NaF = 6.0 moles NaF

Therefore, 3.0 moles of Na react to form 6.0 moles of NaF. Rounded to the tenths place, the answer is 6.0 mol NaF.