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In a class of 20 boys 16 soccer 12 plays hockey and 2 are not allowed to play games how many students plays soccer and hockey

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Answer:

Number of students who play soccer = 16

Number of students who play hockey = 12

Since there are 20 boys in total, and 2 of them are not allowed to play games, there are 20 - 2 = 18 boys who can participate in sports.

S" represent the students who play soccer, "H" for those who play hockey, and "B" for the total number of boys. Using the inclusion-exclusion principle: B = S + H - (S ∩ H)

We know that B (total boys) = 18, S (soccer players) = 16, and H (hockey players) = 12.

solve for S ∩ H:

S ∩ H = 16 + 12 - 18

S ∩ H = 28 - 18

S ∩ H = 10

So, there are 10 students who play both soccer and hockey.

Explanation:

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