Question

2y^2-7g+6=0 solve by completing the square

Answer 1

Explanation:

`2y^2-7y+6=0\\\mathrm{or,\ }2y^2-7y=-6\\\mathrm{or,\ }4(2)(2y^2-7y)=-4(2)(6)\\\mathrm{or,\ }16y^2-56y=-48\\\\mathrm{or,\ }16y^2-56y+(-7)^2=-48+(-7)^2\\\mathrm{or,\ }(4y)^2-2(4y)(7)+7^2=1\\\mathrm{or,\ }(4y-7)^2=1\\\mathrm{or,\ }4y-7=\pm1\\\mathrm{or,\ }4y=7\pm1\\\mathrm{i.e.}\ y=2\ \mathrm{or}\ (3)/(2)`