Question

a bowler accelerates a 6.59 kg bowling ball from rest to 10.3 m/s in 827 ms . what average power does this require of the bowler?

Answer 1

Answer: 422.69W

Step-by-step explanation:

m = 6.59 kg

v₀ = 0 m/s, v = 10.3 m/s

t = 0.827 s

With these values, we can first calculate the work done by the bowler on the ball. To do this, we can calculate the change in the bowling ball's kinetic energy. We need the work since the equation for power is P = W/t.

Δk = k(final) - k(initial)

k = (1/2)mv^2

Since the bowling ball starts at rest, the initial kinetic energy is 0J.

Calculating k(final):

k = (1/2)(6.59)(10.3)^2 = 349.57J

W = Δk = 349.57 - 0 = 349.57J

The work done by the bowler on the bowling ball is 349.57J.

Now, we can use P = W/t to calculate the average power required by the bowler.

P = 349.57/0.827 = 422.69W