Question

15% of all Americans live in poverty. If 41 Americans are randomly selected, find the probability that

a. Exactly 6 of them live in poverty.
b. At most 6 of them live in poverty.
c. At least 5 of them live in poverty.
d. Between 4 and 8 (including 4 and 8) of them live in poverty.

Answer 1

a. Exactly 6 of them live in poverty.

Explanation:

15% of 41 is 6.15, rounding down to 6.