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Two planes, which are 3520 miles apart, fly toward each other. Their speeds differ by 80 mph. If they pass each other in 4 hours, what is the speed of each

Answer 1

Explanation:

Let's assume the speed of one plane is x mph and the speed of the other plane is (x + 80) mph.

When two objects are moving toward each other, their combined speed is the sum of their individual speeds. In this case, the combined speed of the two planes is:

x + (x + 80) = 2x + 80 mph

The distance traveled by both planes is 3520 miles. We can set up the equation:

Distance = Speed × Time

For the first plane:

Distance = x mph × 4 hours = 4x miles

For the second plane:

Distance = (x + 80) mph × 4 hours = 4(x + 80) miles

Since they are 3520 miles apart, their combined distances should add up to 3520 miles:

4x + 4(x + 80) = 3520

Now, let's solve for x:

4x + 4x + 320 = 3520

8x + 320 = 3520

8x = 3520 - 320

8x = 3200

x = 3200 / 8

x = 400

So, the speed of one plane is 400 mph, and the speed of the other plane is (400 + 80) = 480 mph.