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A gas station wishes to make 100L of 48% ethylene by mixing some 40% solution with some 60% solution of ethylene. How much of each solution should the attendant use?

User Shijin
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Answer:

.40x + .60(100 - x) = .48(100)

.40x + 60 - .60x = 48

.20x = 12

x = 60 L of 40% ethylene

100 - 60 = 40 L of 60% ethylene

User Niels Bosman
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