Answer:
E = 1/2 I ω^2 + 1/2 M V*2 total kinetic energy of ball
E = 1/2 M R^2 * (V / R)^2 + 1/2 M V^2 = M V^2 total KE of rolling ball
F = 1/2 M g sin θ force acting down incline of ball
F h = E where h is the distance in height thru which F must act
M V^2 = 1/2 L M g sin θ = 1/2 h M g (since h = L * sin θ)
h = 2 * V^2 / g maximum height of ball on incline of θ
h = 2 * (2.8 m/s)^2 / 9.80 m/s^2 = 1.6 m