Answer:
Step-by-step explanation:
The magnitude of the magnetic force that each charge exerts on the other is:
```
F = (μ0 * q1 * q2) / (2 * π * r^2)
```
where:
* μ0 is the permeability of free space (4π * 10^-7 T * m / A)
* q1 and q2 are the charges of the two particles (in coulombs)
* r is the distance between the two particles (in meters)
In this case, we are given that q1 = q2 = 1 μC and r = 1 m. Plugging these values into the equation, we get:
```
F = (μ0 * 1 * 1) / (2 * π * 1^2) = 2 * 10^-7 N
```
Therefore, the magnitude of the magnetic force that each charge exerts on the other is 2 * 10^-7 N.
To express the answer in newtons, we can use the following conversion factor:
```
1 N = 10^5 dynes
```
Therefore, the magnitude of the magnetic force that each charge exerts on the other is:
```
F = 2 * 10^-7 N = 2 * 10^-2 dynes
```