Question

PLS HELP! I WILL GIVE BRIANLIEST

Answer 1

∡A = ∡
`\boxed{\tt C}` being the base angle of an isosceles triangle of ΔABC

ΔAKE ≅ ΔCKP by
`\boxed{\tt ASA\: axiom}`

Explanation:

Given:

AB ≅ BC

AK ≅ KC

∡AKE ≅ ∡CKP

To prove:

ΔAKE ≅ ΔCKP

Solution:

Since AB ≅ BC

It means that

∡A = ∡C being the base angle of an isosceles triangle

In ΔAKE and ΔCKP

∡AKE ≅ ∡CKP Given Angle

AK ≅ KC Given Side

∡A = ∡C being the base angle of an isosceles triangle of ΔABC

Therefore,

ΔAKE ≅ ΔCKP by ASA axiom