To calculate the kinetic energy gained by the object, we can use the formula:
KE = (1/2)mv^2
where KE is the kinetic energy, m is the mass of the object, and v is its velocity.
Plugging in the values, we get:
KE = (1/2)(16 x 10^-9 kg)(309.2 m/s)^2
KE = 7.61 x 10^-6 J
Therefore, the object gained approximately 7.61 x 10^-6 Joules of kinetic energy.
To calculate the velocity of the object, we can use the formula:
ΔPE = qΔV
where ΔPE is the change in electric potential energy, q is the charge of the object, and ΔV is the change in voltage.
Solving for the change in electric potential energy, we get:
ΔPE = (-630 x 10^-9 C)(5 V - 0 V)
ΔPE = -3.15 x 10^-6 J
The change in electric potential energy is equal to the kinetic energy gained by the object, so we can set ΔPE = KE and solve for v:
(1/2)mv^2 = -3.15 x 10^-6 J
v^2 = (-2)(-3.15 x 10^-6 J)/m
v = √(6.30 x 10^-6 J/16 x 10^-9 kg)
v = 309.2 m/s
Therefore, the object is moving at approximately 309.2 meters per second.