The total energy required to bring 2 kg of ice from -5°C to 115°C is approximately 535,400 joules. This is calculated by using the specific heat capacity of water which is 4.18 J/g°C and multiplying that by the mass of ice (2kg) the change in temperature 120 °C, and the heat of fusion of water, which is approximately 334,000 J/kg. It is important to note that this calculation assumes that the ice is completely converted to water and then to steam.