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14) A nicotine patch prescribed for 16 weeks, 21mg/patch daily for the first 6 weeks,

14mg/patch daily for the next wein, and 7mg/day daily for the following weeks, then the
process was terminated. How many mg of nicotine will the patent alie

A. 1513 mg
B. 1470 mg
C. 1385 mg
D. 1520 mg
E. 1395 mg

1 Answer

3 votes

Answer:

D

Explanation:

To calculate the total amount of nicotine the patient will receive, we need to break down the dosage for each week.

In the first week, the patient receives 14 mg of nicotine per patch daily. If we assume that the patient wears one patch per day, then the total nicotine intake for the first week is 14 mg x 7 days = 98 mg.

In the following weeks, the patient receives 7 mg of nicotine per day. Let's assume the following weeks continue for a total of n weeks. So the total nicotine intake for the following weeks is 7 mg x n weeks.

Since the process was terminated after the following weeks, we need to find the value of n. Let's say the process lasted for a total of m weeks, including the first week. So, the total nicotine intake for m weeks is:

98 mg + (7 mg x n weeks)

We know that the total nicotine intake for m weeks is equal to 1520 mg (which is the answer given in option D).

So, we can write the equation:

98 mg + (7 mg x n weeks) = 1520 mg

Now, let's solve for n:

7n + 98 = 1520

Subtract 98 from both sides:

7n = 1422

Divide both sides by 7:

n = 1422 / 7

n ≈ 203

Therefore, the patient will receive an additional 7 mg of nicotine daily for 203 weeks after the first week.

To find the total amount of nicotine the patient will receive, we can substitute the value of n back into the equation:

Total nicotine intake = 98 mg + (7 mg x 203 weeks) = 98 mg + 1421 mg = 1519 mg

Rounding to the nearest whole number, the patient will receive approximately 1520 mg of nicotine.

Therefore, the correct answer is D. 1520 mg.

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