Question

is the concentration of a solution formed by diluting 19.0 of a 7.4 M fructose solution to 410. mL? Be sure your answer has the correct number of nificant figures.

Answer 1

0.343 M

Step-by-step explanation:

To solve this problem, we can use the formula for dilution:

`M_1M_2=V_1V_2`

• where
  `M_1` is the initial concentration of the solution,
  `V_1` is the initial volume of the solution,
  `M_2` is the final concentration of the solution, and
  `V_2` is the final volume of the solution.

Plugging in the given values, we get:

`(7.4M)(19.0mL)=M_2(410. mL)`

`M_2=((7.4M)(19.0mL))/((410.mL))`

`M_2=0.343M`

Therefore, the concentration of the solution formed by diluting
`19.0mL` of a
`7.4M` fructose solution to
`410. \text{mL}` is
`0.343M`, rounded to three significant figures.

Answer 2

To find the concentration of the solution after dilution, we can use the formula:

M1V1 = M2V2

Where:
M1 = initial concentration of the solution
V1 = initial volume of the solution
M2 = final concentration of the solution
V2 = final volume of the solution

Given:
M1 = 7.4 M
V1 = 19.0 mL (Note: convert to liters by dividing by 1000)
M2 = ?
V2 = 410 mL (Note: convert to liters by dividing by 1000)

Converting V1 and V2 to liters:
V1 = 19.0 mL / 1000 = 0.019 L
V2 = 410 mL / 1000 = 0.410 L

Using the formula, we can solve for M2:
M1V1 = M2V2
(7.4 M)(0.019 L) = M2(0.410 L)

M2 = (7.4 M)(0.019 L) / 0.410 L

Calculating the result:
M2 = 0.343 M

Therefore, the concentration of the solution after dilution is 0.343 M.