Answer:
Y=2x²-3x-2....eqn 1
(I) .'. dy/dx=4x-3....eqn 2
substituting x=0 on eqn 2 .'. M= -3....Gradient=-3 .'. M1= -3
(II) substituting x=0 on eqn 1....Y= -2
(III) M2= -1/M2
.'. M2= -1/-3 .'. M2 = 1/3
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