Answer:
Step-by-step explanation:
One example of a molecule that satisfies all the given conditions is Pyridine (C5H5N). Here's an overview of how it meets each condition:
1. Pyridine contains carbon (C), hydrogen (H), nitrogen (N), oxygen (O), and halogen (none in this case, but it meets the condition).
2. Pyridine has a π bond in its structure. It has a six-membered aromatic ring with alternating double and single bonds, which includes a π bond.
3. Pyridine contains polar bonds. The nitrogen atom in pyridine is more electronegative than carbon and hydrogen, resulting in a polar C-N bond.
4. The nitrogen atom in pyridine has sp2 hybridization. It forms three sigma bonds, with one electron pair in the p orbital.
5. Pyridine has a bond with the specified bonding scheme. In pyridine, the nitrogen atom (N) has sp2 hybridization and forms a sigma bond with a carbon atom (C) that is in an sp2 hybridized state.
6. Pyridine also has a bond with the specified bonding scheme. The nitrogen atom (N) in pyridine has an sp3 hybridization and forms a sigma bond with a hydrogen atom (H), which is in a 1s orbital.
7. Pyridine has a six-membered ring composed of five carbon atoms and one nitrogen atom, meeting the requirement of having at least one six-member ring.
Please note that Pyridine is just one example that satisfies the given conditions. There could be other molecules as well that fulfill these requirements.