0 Comments
Explanation:
log8 (x+1) + log8 (x-1) = 1
Using rules of logs, this is the same as
log8 ( (x+1)(x-1) ) = 1
log8 ( x^2 -1) = 1 Use rules of logs again to reduce to:
x^2- 1 = 8^1
x^2 = 9
x = ± 3
x = +3 ( -3 would make a negative log...not allowed)
9.4m questions
12.2m answers