Question

Use the Quadratic Formula to solve the equation 4x^2+1=8x

Answer 1

`x=1\pm(√(3))/(2)`

Explanation:

`\displaystyle 4x^2+1=8x\\4x^2-8x+1=0\\\\x=(-b\pm√(b^2-4ac))/(2a)\\\\x=(-(-8)\pm√((-8)^2-4(4)(1)))/(2(4))\\\\x=(8\pm√(64-16))/(8)\\\\x=(8\pm√(48))/(8)\\\\x=(8\pm4√(3))/(8)\\\\x=1\pm(√(3))/(2)`