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Brad recorded the number of visitors at the local science museum during the week

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Assuming it's the same one, I found the question you want answering online in its entirety.

The observed and expected frequencies are:

Day Observed Frequency Expected Frequency

Tuesday 18 25

Wednesday 24 25

Thursday 28 25

Friday 30 25

The formula to calculate the chi-squared test statistic is:

χ² = Σ [(Observed frequency - Expected frequency)² / Expected frequency]

Plugging in the values from the table above, we get:

χ² = [(18-25)²/25] + [(24-25)²/25] + [(28-25)²/25] + [(30-25)²/25]

= 1.44 + 0.04 + 0.36 + 1.44

= 3.28

To find the critical value for the chi-square test with 3 degrees of freedom and a significance level of 0.10, we can consult a chi-square distribution table or use a calculator. The critical value is 6.25.

Since the calculated chi-square test statistic (3.28) is less than the critical value (6.25), we fail to reject the null hypothesis that the number of visitors each day follows a uniform distribution with a mean of 25 visitors per day. Therefore, we can conclude that there is not enough evidence to suggest that the number of visitors does not follow a uniform distribution.

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