Assuming it's the same one, I found the question you want answering online in its entirety.
The observed and expected frequencies are:
Day Observed Frequency Expected Frequency
Tuesday 18 25
Wednesday 24 25
Thursday 28 25
Friday 30 25
The formula to calculate the chi-squared test statistic is:
χ² = Σ [(Observed frequency - Expected frequency)² / Expected frequency]
Plugging in the values from the table above, we get:
χ² = [(18-25)²/25] + [(24-25)²/25] + [(28-25)²/25] + [(30-25)²/25]
= 1.44 + 0.04 + 0.36 + 1.44
= 3.28
To find the critical value for the chi-square test with 3 degrees of freedom and a significance level of 0.10, we can consult a chi-square distribution table or use a calculator. The critical value is 6.25.
Since the calculated chi-square test statistic (3.28) is less than the critical value (6.25), we fail to reject the null hypothesis that the number of visitors each day follows a uniform distribution with a mean of 25 visitors per day. Therefore, we can conclude that there is not enough evidence to suggest that the number of visitors does not follow a uniform distribution.