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Let f(x)=x³+6x²−36x+8

(a) Find
f′(x)= ....
(b) Find f′′(x)= ...
(c) On what set is f increasing?
interval of increase: (-1[infinity])
(d) On what set is f decreasing?
interval of decrease: ...
(e) On what set is f concave downward?
interval of downward concavity : ...
(f) On what set is f Concave upward?
interval of upward concavity : ...

1 Answer

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Step-by-step explanation: (a) To find the derivative of f(x), we differentiate each term of the function:

f(x) = x³ + 6x² - 36x + 8

Using the power rule, the derivative is:

f'(x) = 3x² + 12x - 36

Therefore, f'(x) = 3x² + 12x - 36.

(b) To find the second derivative of f(x), we differentiate the derivative f'(x):

f'(x) = 3x² + 12x - 36

Differentiating each term:

f''(x) = 6x + 12

Therefore, f''(x) = 6x + 12.

(c) To determine where f is increasing, we need to find where the first derivative is positive (greater than 0).

Setting f'(x) > 0 and solving for x:

3x² + 12x - 36 > 0

Factoring the quadratic equation:

3(x² + 4x - 12) > 0

Now, we can find the interval of increase by analyzing the sign of the quadratic expression:

x² + 4x - 12 > 0

The quadratic equation factors as:

(x + 6)(x - 2) > 0

From this, we can determine the sign of the expression for different intervals:

Interval (-∞, -6): (-)(-) > 0, which is false.

Interval (-6, 2): (-)(+) > 0, which is true.

Interval (2, ∞): (+)(+) > 0, which is true.

Therefore, the interval of increase for f(x) is (-6, 2).

(d) To determine where f is decreasing, we need to find where the first derivative is negative (less than 0).

Setting f'(x) < 0 and solving for x:

3x² + 12x - 36 < 0

Using the same quadratic expression, we can determine the sign of the expression for different intervals:

Interval (-∞, -6): (-)(-) < 0, which is true.

Interval (-6, 2): (-)(+) < 0, which is false.

Interval (2, ∞): (+)(+) < 0, which is false.

Therefore, the interval of decrease for f(x) is (-∞, -6).

(e) To determine where f is concave downward, we need to find where the second derivative is negative (less than 0).

Setting f''(x) < 0 and solving for x:

6x + 12 < 0

Simplifying the inequality:

x + 2 < 0

Solving for x:

x < -2

Therefore, the interval of downward concavity for f(x) is (-∞, -2).

(f) To determine where f is concave upward, we need to find where the second derivative is positive (greater than 0).

Setting f''(x) > 0 and solving for x:

6x + 12 > 0

Simplifying the inequality:

x > -2

Therefore, the interval of upward concavity for f(x) is (-2, ∞).

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