129k views
2 votes
Given the following piecewise function, evaluate lim

x→1

f(x). (If the limit does not exist, enter Ø.) f(x)=





2x
2
−3x−2
−2x
2
+3x−2
−2x
2
−1


if x≤−4
if −4 if x>1


User Sasse
by
8.8k points

1 Answer

1 vote

Answer:

Step-by-step explanation: To evaluate the limit as x approaches 1 for the given piecewise function, we need to consider the right-hand limit and the left-hand limit separately.

Right-hand limit (x → 1+):

For x > 1, the function is defined as -2x^2 + 3x - 2.

Substituting x = 1 into the function: -2(1)^2 + 3(1) - 2 = -1.

Left-hand limit (x → 1-):

For x ≤ -4, the function is defined as 2x^2 - 3x - 2.

Since x = 1 is not within the specified range, we cannot evaluate the left-hand limit at x = 1.

Since the right-hand limit (-1) is defined, but the left-hand limit is not defined for x = 1, the limit as x approaches 1 for the given function does not exist (Ø).

User Ahadortiz
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories