Question

What is the value of -7(x^2-6)+2y when x=2 and y=-6? A. –1 B. 0 C. 1 D. 2

Answer 1

D. 2

Explanation:

-7(x^2 - 6) + 2y

x = 2

y = 6

Substitute the variables:

-7(2^2 - 6) + 2(-6)

2^2 = 4:

-7(4 - 6) + 2(-6)

4 - 6 = -2:

-7(-2) + 2(-6)

-7 * -2 = 14:

14 + 2(-6)

2 * -6 = -12:

14 + (-12)

14 + (-12) = 14 - 12:

14 - 12

14 - 12 = 2:

2

26

Answer 2

2

Explanation:

-7(x^2-6)+2y

Let x = 2 and y = -6

-7( 2^2-6)+2(-6)

Exponents first

-7(4 -6)+2(-6)

Parentheses next

-7( -2)+2(-6)

Multiply

14 -12

Subtract

2