Question

10. Find the area of the region enclose by the curves \( y=x^{2}+2, y=-x \), \( x=0 \) and \( x=1 \). (a) \( \frac{31}{3} \) (b) \( \frac{17}{6} \) (c) \( \frac{1}{3} \) (d) \( \frac{17}{3} \)

Answer 1

Hi,

answer b 17/6

Explanation:

`\displaystyle \int\limits^0_1 {x^2+2} \, dx =[(x^3)/(3) +2x]_0^1=(1)/(3)+2=(7)/(3) \\\\\\\boxed{(7)/(3) +(1)/(2) =(17)/(3) }\\`