Question

( PLEASE HELP ) A submarine sandwich created for a party is measured to be 63 inches long. This sandwich is cut into thirds. One of the resulting pieces is again cut into thirds . Before serving it, one of these pieces is cut in half. Of the final 6 pieces , what is the difference in length between one of the two longest pieces and one of the two smallest pieces? A. 3.5 in. B. 10.5 in. C. 17.5 in . D. 21.0 in

Answer 1

A submarine sandwich is 63 inches long. When you cut it into thirds, each piece is 21 inches long. One of the pieces is cut into thirds again, so the resulting pieces are 7 inches long. One of these pieces is cut in half, so the resulting pieces are 3.5 inches long.

The two longest pieces are 21 inches long and the two smallest pieces are 3.5 inches long. The difference in length between the two longest pieces and the two smallest pieces is 21 - 2(3.5) = 17.5 inches. So the answer is C.

Does that make sense? Let me know if you have any other questions.

Answer 2

(C) 17.5 in

Explanation:

If the 63-inch sandwich is cut into thirds, each piece will be:

⇒ 63 / 3 = 21 inches long

One of these pieces is cut into thirds, so each resulting piece will be:

⇒ 21 / 3 = 7 inches long

Now we have five pieces that are 21 inches long and two pieces that are 7 inches long. One of the 7-inch pieces is cut in half, so we have six pieces of the following lengths:

⇒ 21, 21, 21, 21, 7, 3.5

The two smallest pieces are both 3.5 inches long, and the two longest pieces are both 21 inches long. The difference in length between one of the two longest pieces and one of the two smallest pieces is:

⇒ 21 - 3.5 = 17.5 inches

Therefore, the answer is (C) 17.5 in.