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Part B

Complete the proof of the vertical angles theorem.
Given: Lines AB and CD intersect at point E.
Prove: Angle AED is congruent to angle BEC.
(ENTER THE MISSING STATEMENTS AND REASONS IN THE TABLE)

Part B Complete the proof of the vertical angles theorem. Given: Lines AB and CD intersect-example-1

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Answer:

PROOF:(1) m∠1 + m∠2 = 180° // straight line measures 180° (2) m∠3 + m∠2 = 180° // straight line measures 180(3) m∠1 + m∠2 = m∠3 + m∠2 // transitive property of equality, as both left-hand sides of the equation sum up to the same value (180° )(4) m∠1 = m∠3 // subtraction property of equality (subtracted m∠2 from both sides)(5) ∠1 ≅ ∠3 // definition of congruent anglesSimilarly, for ∠2 ≅∠4:(1) m∠3 + m∠2 = 180° // straight line measures 180° (2) m∠3 + m∠4 = 180° // straight line measures 180°(3) m∠3 + m∠2 = m∠3 + m∠4 // transitive property of equality, as both left hand sides of the equation sum up to the same value (180°)(4) m∠2 = m∠4 // subtraction property of equality (subtracted m∠3 from both sides)(5) ∠2 ≅ ∠4 // definition of congruent angleAnd thus, we have proven the theorem.QUOD ERAT DEMONSTRANDUMOften, you will see proofs end with the Latin phrase "quod erat demonstrandum”, or QED for short, which means “what had to be demonstrated” or “what had to be shown”. There is also a special charter sometimes used - (∎).STRATEGY: HOW TO SOLVE SIMILAR PROBLEMSOk, great, I’ve shown you how to prove this geometry theorem. But suppose you are now on your own –how would you know how to do this?Well, in this case, it is quite simple. All we were given in the problem is a couple of intersecting lines. And the only definitions and proofs we have seen so far are that a line’s angle measure is 180°, and that two supplementary angles which make up a straight line sum up to 180°.

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