1.8k views
1 vote
Solve 4u^(2)+8u=-1 by using the quadratic formula.

2 Answers

7 votes

Answer:

-1+
√(3)/2, -1-
√(3)/2

Explanation:

Quadratic formula= -b±
\sqrt{b^(2)-4ac } / 2a

4
u^(2)+8u=-1

add 1 to both sides

4
u^(2)+8u+1=0

a b c

label numbers with a,b,c

a=4

b=8

c=1

substitute into the quadratic formula

-b±
\sqrt{b^(2)-4ac } / 2a

-8±
\sqrt{8^(2)-4(4)(1) / 2(4)

solve

-8±
\sqrt{8^(2)-4(4)(1) / 2(4)

-8±
√(64-16) /8

-8±
√(48) /8

-8±4
√(3) /8

-8+4
√(3) /8, -8-4
√(3) /8

-1+
√(3)/2, -1-
√(3)/2

User Guiweb
by
8.6k points
6 votes

Answer:

-1 + sqrt(3)/2 or -1 - sqrt(3)/2

Explanation:

First we rewrite the equation in the form of ax^2 + bx + c = 0.

Add 1 to both sides. 4u^2 + 8u + 1 = 0. Then we apply the quadratic formula -b plus minus root b^2 - 4ac all over 2a. Plug the values for a b and c in, and you should get your two possible answers - either -1 + sqrt(3)/2 or -1 - sqrt(3)/2.

User Piidro
by
8.9k points

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