Question

Determine the change in volume that takes place when a 2.11−L sample of N2(g) is heated from 250.0 K to 476.0 K.

Answer 1

1.89 L

Step-by-step explanation:

We are given an initial volume of 2.11 L of N2 gas at 250.0 K

We need to find the change in volume when the temperature changes to 476.0 K

From the ideal gas law, we know the volume of a gas is directly proportional to its temperature:

V ∝ T

This means that when temperature increases, volume also increases, and vice versa.

We can use the formula for proportionality to find the change in volume

ΔV ∝ ΔT

Plugging in the given values:

Initial volume (V1) = 2.11 L

Initial temperature (T1) = 250.0 K

Final temperature (T2) = 476.0 K

Calculating the change in temperature:

ΔT = T2 - T1 = 476.0 K - 250.0 K = 226.0 K

Using proportionality:

ΔV/V1 = ΔT/T1

ΔV = (V1)(ΔT/T1)

= (2.11 L)(226.0 K / 250.0 K)

= 1.89 L

Therefore, the change in volume is 1.89 L when the N2 gas is heated from 250.0 K to 476.0 K.

Answer 2

Answer: Increase of 4.02L

Step-by-step explanation:

Charles Law: V₁ / T₁ = V₂ / T₂

First V and First T = intial volume and temp.
Second V and T = final volume and temp.

Initial V =2.11L
Initial T = 250K
Final T = 476K

Rearranging equation: V₂ = (V₁ * T₂) / T₁

V₂ = (2.11L * 476K)/250K

V₂ = 4.02L