Question

which image depicts the transfer of electrons between strontium and fluorine when they form an ionic compound

Answer 1

A

Step-by-step explanation:

Answer 2

The image you sent shows four Lewis dot structures for the transfer of electrons between strontium and fluorine when they form an ionic compound. The correct answer is C.
`Sr^(+2)2[:\dot{F}^(-1)].`

Step-by-step explanation:

* Strontium has two valence electrons, while fluorine has seven.

* To form an ionic compound, strontium will transfer its two valence electrons to fluorine to form a full octet.

* This will result in strontium becoming a positively charged ion,
`Sr^(+2)`, and fluorine becoming a negatively charged ion,
`F^(-1)`.

* The Lewis dot structure for the ionic compound strontium fluoride,
`$SrF_2$`, is therefore
`Sr^(+2)2[:\dot{F}^(-1)]`.

The other Lewis dot structures are incorrect:

* **A. $
`F_(\bullet)^(\bullet\bullet)-Sr-F_(\bullet)^(\bullet\bullet)$`** shows the atoms before they have formed an ionic compound, so the electrons are not distributed correctly.

* B. SE: shows a single bond between strontium and fluorine, but an ionic bond is formed by the transfer of electrons, not by sharing electrons.

* D.
`F Sr F:` shows the atoms after they have formed an ionic compound, but the electrons are not distributed correctly.