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Question 4 Find the value of the summation. ∑

k=1
3

2
k
= ∫
−4
3

(6x
5
+2x
4
)dx Question 9 Evaluate the definite integral. ∫
0
4
π



sin(4t)dt ∫(5x
4
+2x
2
)dx

User Alemjerus
by
7.8k points

1 Answer

5 votes

Answer:

sum_(k=1)^3 2^k

Explanation:

Its easy. ;)

User Linusg
by
8.4k points