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Question 4 Find the value of the summation. ∑ k=1 3 2 k = ∫ −4 3 (6x 5 +2x 4 )dx Question 9 Evaluate the definite integral. ∫ 0 4 π sin(4t)dt ∫(5x 4 +2x 2 )dx
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Nov 28, 2024
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Question 4 Find the value of the summation. ∑
k=1
3
2
k
= ∫
−4
3
(6x
5
+2x
4
)dx Question 9 Evaluate the definite integral. ∫
0
4
π
sin(4t)dt ∫(5x
4
+2x
2
)dx
Mathematics
high-school
Alemjerus
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Alemjerus
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Answer:
sum_(k=1)^3 2^k
Explanation:
Its easy. ;)
Linusg
answered
Dec 2, 2024
by
Linusg
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